Question

The sum of three consecutive multiples of 9 is 999. find the multiples

Answer 1

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Answer 2

hello users ....

solution:-
let first multiple of 9 is = 9x 
Because they are consecutive 
=> second multiple of 9 = 9 (x + 1) 
And
third multiple of 9 = 9(x+2) 

Now,
According to question :
sum of these numbers
=> 9x + 9(x+1) + 9(x +2) = 999

=> 9 [ x + (x+1) + (x +2) ] = 9 * 111

=> x + (x+1) + (x+2) = 111 

=> 3x = 111 - 3 = 108

=> x = 36 

Hence :
first number multiple of 9 = 9x
= 9*36 = 324
Second number = 9(x+1)
 = 9*(36+1) = 9*37 = 333
And
third number multiple of 9 = 9(x+2)
= 9 * (36+2) = 9 * 38 = 342 Answer 

@ hope it helps :)