Question

the sum of three numbers whose ratios are 10/3:21/5:49/8 is 4917. Find the numbers

Answer 1

➡HERE IS YOUR ANSWER⬇

The ratio of the numbers is

10/3 : 21/5 : 49/8

Let, x be the common multiple.

Then the numbers are

10x/3, 21x/5 and 49x/8

Given that :

10x/3 + 21x/5 + 49x/8 = 4917

or, (10/3 + 21/5 + 49/8)x = 4917

or, 1639x/120 = 4917

or, 1639x = 4917×120

or, x = (4917×120)/1639

or, x = 3×120 [since 4917=3×1639]

So, x = 360

Therefore, the numbers are

1200, 1512 and 2205.

⬆HOPE THIS HELPS YOU⬅

Answer 2

$\frac{10}{3} : \frac{21}{5} : \frac{49}{8} = 4917 \\ \\ LCM \: \: of \: \: 3, \: \: 5, \: \: 8 \: \: is \: \: 120 \\ \frac{120}{3} = 40 \\ \frac{120}{5} = 24 \\ \frac{120}{8} = 15 \\ \\ \frac{10}{3} x + \frac{21}{5} x + \frac{49}{8} x = 4917 \\ \frac{(10x \times 40) + (21x \times 24) + (49x \times 15)}{120} = 4917 \\ \frac{400x + 504x + 735x}{120} = 4917 \\ \frac{1639x}{120} = 4917 \\ 1639x = 4917 \times 120 \\ 1639x = 590040 \\ x = \frac{590040}{1639} \\ \large{ \boxed{x = \underline{ \underline{360}}}} \\ \\ \frac{10}{3} x⇒ \frac{10}{3} \times 360 ⇒1200 \\ \frac{21}{5} x⇒ \frac{21}{5} \times 360⇒1512 \\ \frac{49}{8} x⇒ \frac{49}{8} \times 360⇒2205 \\ \\ \frac{10}{3} : \frac{21}{5} : \frac{49}{8} = 4917 \\ \frac{10}{3}x : \frac{21}{5}x : \frac{49}{8}x = 4917 \\ \large{ \bf{1200 : 1512 : 2205 = 4917}} \\ \\ 1200 + 1512 + 2205 = 4917$