The sum of two consecutive multiples of 7 is 161.Find these multiples
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Let, the two consecutive multiplies of 7 are 7x and 7(x+1).
7x+7(x+1)= 161
7x+7x+1= 161
14x= 161-7
14x= 154/14
x= 11
*7 x 11=77
*7 x 12= 84
77+84=> 161 answer.
7x+7(x+1)= 161
7x+7x+1= 161
14x= 161-7
14x= 154/14
x= 11
*7 x 11=77
*7 x 12= 84
77+84=> 161 answer.
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