The sum of two digit number formed by interchanging the digit is 132 if 12 is added to the number the new number become 5 times the sum of digits
Answers
Answer:
48
Step-by-step explanation:
Let say two digits number = xy
Value of number = 10x + y
Interchanged number = yx
Value of interchanged number = 10y + x
Number + interchanged number = 132
10x + y + 10y + x = 132
11x + 11y = 11×12
x + y = 12 EQ 1
Sum of two digits = x + y
so sum of digits = 12 from EQ 1
12 is added to number = 5 × Sum of Digits
10x + y + 12 = 5 × 12
10 x + y = 48 EQ 2
EQ 2 - EQ 1
10x + y - x - y = 48 -12
9x = 36
x = 4
4 + y = 12
y = 8
number = 48
Answer:
Let the number be xy = 10x + y
Number obtained by interchanging the digits = yx = 10y + x
From the given information, we have:
10x + y + 10y + x = 132 11x + 11y = 132 x + y = 12 ... (1)
Also, we have:
10x + y + 12 = 5(x + y) 10x + y + 12 - 5x - 5y = 0 5x - 4y + 12 = 0 ... (2)
Multiplying (1) by 4, we get 4x + 4y - 48 = 0 ...
(3) Adding (2) and (3), we get, 9x - 36 = 0 x = 4 So, y = 12 - 4 = 8
Thus, the number is 48.
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