Question

the sum of two no. is 7 .if their sum is 7 times their difference,then find the no.

Answer 1

Hey


Let the two numbers be x and y .


Now ,


x + y = 7


=> x = 7 - y


And ,

difference = x - y


A / q ,


x + y = 7 ( x - y )


Because sum is 7 times their difference .


=> x + y = 7x - 7y


=> 7x - x - 7y - y = 0


=> 6x - 8y = 0


=> 2 ( 3x - 4y ) = 0

=> 3x - 4y = 0


putting the value of x in this eq , we get


=> 3 ( 7 - y ) - 4 y = 0

=> 21 - 3y - 4y = 0


=> - 7y = -21


=> y = 3 .


So ,

x = 7 - y


= 7 - 3


= 4


thanks :)

Answer 2

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