Math, asked by vvvvvsssss, 11 months ago

The sum of two numbers is -3 if one of the number is -17/5 then the other number is

Answers

Answered by Anonymous
8

Answer :-

The required number is 2/5.

Solution :-

Sum of two numbers = - 3

One of the number = - 17/5

Let the another number be x

According to the question :-

⇒ - 17/5 + x = - 3

Transpose - 17/5 to RHS

⇒ x = - 3 + 17/5

⇒ x = - 3/1 + 17/5

Taking LCM

⇒ x = - 3(5)/1(5) + 17/5

⇒ x = - 15/5 + 17/5

⇒ x = 2/5

Therefore the required number is 2/5.

Verification :-

- 17/5 + x = - 3

Substitute x = 2/5 in the above equation

⇒ - 17/5 + 2/5 = - 3

⇒ (- 17 + 2)/5 = - 3

⇒ - 15/5 = - 3

⇒ - 3 = - 3

Answered by shikhaku2014
13

 \Huge{\mathbb{\boxed{\boxed{\underline{\pink{SOLUTION }}}}}}

Let the other number be x

It is given that the sum of two number is - 3

And one of the no. is - 17/5

According to the question

 \huge{\frac{-17}{5}}  + x =  - 3

\large{ =  >  x  =  - 3  + \frac{17}{5}}

LCM of both the number is 5

 \large{=  > x =   \frac{ - 3 \times 5}{1 \times 5}  +  \frac{17 \times 1}{5 \times 1}}

 \large{=  >  x =  \frac{ - 15 + 17}{5}}

2\5 Answer

 \large{\mathcal{\boxed{\boxed{\underline{\red{VERIFICATION}}}}}}

To verify it put the value of x

\large{ =  >  \frac{ - 17}{5}  +  \frac{2}{5}  =  - 3}

\large{ =  >  \frac{ - 17 + 2}{5}  =  - 3}

\large{ =  >   \frac{ - 15}{5}  =  - 3}

\dfrac{\cancel{-15}}{\cancel{5}}=-3

 =  >  - 3 =  - 3

LHS = RHS

hence, it is verified.

Therefore, the answer is 2/5

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