Question

The sum of two numbers is -3 if one of the number is -17/5 then the other number is

Answer 1

Answer :-

The required number is 2/5.

Solution :-

Sum of two numbers = - 3

One of the number = - 17/5

Let the another number be x

According to the question :-

⇒ - 17/5 + x = - 3

Transpose - 17/5 to RHS

⇒ x = - 3 + 17/5

⇒ x = - 3/1 + 17/5

Taking LCM

⇒ x = - 3(5)/1(5) + 17/5

⇒ x = - 15/5 + 17/5

⇒ x = 2/5

Therefore the required number is 2/5.

Verification :-

- 17/5 + x = - 3

Substitute x = 2/5 in the above equation

⇒ - 17/5 + 2/5 = - 3

⇒ (- 17 + 2)/5 = - 3

⇒ - 15/5 = - 3

⇒ - 3 = - 3

Answer 2

$\Huge{\mathbb{\boxed{\boxed{\underline{\pink{SOLUTION }}}}}}$

Let the other number be x

It is given that the sum of two number is - 3

And one of the no. is - 17/5

According to the question

$\huge{\frac{-17}{5}} + x = - 3$

$\large{ = > x = - 3 + \frac{17}{5}}$

LCM of both the number is 5

$\large{= > x = \frac{ - 3 \times 5}{1 \times 5} + \frac{17 \times 1}{5 \times 1}}$

$\large{= > x = \frac{ - 15 + 17}{5}}$

2\5 Answer

$\large{\mathcal{\boxed{\boxed{\underline{\red{VERIFICATION}}}}}}$

To verify it put the value of x

$\large{ = > \frac{ - 17}{5} + \frac{2}{5} = - 3}$

$\large{ = > \frac{ - 17 + 2}{5} = - 3}$

$\large{ = > \frac{ - 15}{5} = - 3}$

$\dfrac{\cancel{-15}}{\cancel{5}}=-3$

$= > - 3 = - 3$

LHS = RHS

hence, it is verified.

Therefore, the answer is 2/5