the surface area of 3 adjacent faces of a cube are x,y,,z respectively find the volume of cube
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• Let the length be = l
• Let the breadth be = b
• Let the height be = h
Now area of base = l * b
= lb –––– ( i )
Area of it's adjacent side
= bh –––– ( ii )
Area of one of it's adjacent side
= lh –––– ( iii )
Now ,
Eq ( i ) * eq ( ii ) * eq ( iii )
= lb * bh * lh
= l ² * b ² * h ² .
Also given that areas are :- x , y , and z respectively .
So
l ² * b ² * h ² = xyz
=> ( l b h ) ² = xyz
=> l b h = √ xyz
And we know that
volume = l b h
So volume = √ xyz .
thanks :)
• Let the length be = l
• Let the breadth be = b
• Let the height be = h
Now area of base = l * b
= lb –––– ( i )
Area of it's adjacent side
= bh –––– ( ii )
Area of one of it's adjacent side
= lh –––– ( iii )
Now ,
Eq ( i ) * eq ( ii ) * eq ( iii )
= lb * bh * lh
= l ² * b ² * h ² .
Also given that areas are :- x , y , and z respectively .
So
l ² * b ² * h ² = xyz
=> ( l b h ) ² = xyz
=> l b h = √ xyz
And we know that
volume = l b h
So volume = √ xyz .
thanks :)
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