the taxi fare in a city as follows for the first km the taxi fare is rupees 10 and for subsequent distance it is rupees 6 per km taking distance as x km and total fare as y rupees write a linear equation
(a)from the equation find the fare of distance 10 km
(b)find the distance traveled if the total fare is rupees 54
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y = 6(x-1) + 10
y = 6x + 4
b. for 10 km x = 10
y = 6(10) + 4
y = ₹ 64
c. 54 = 6x + 4
6x = 50
x = 25/3 km
y = 6x + 4
b. for 10 km x = 10
y = 6(10) + 4
y = ₹ 64
c. 54 = 6x + 4
6x = 50
x = 25/3 km
navyaseeram:
thank you
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