The temperature of 840g of vegetable oil is raised by adding 110 kJ of heat. The initial
temperature of the oil is 18C and its specific heat capacity is 2,220 J kg-1 K-1.
Calculate the final temperature of the water. SHOW FULL WORKING
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Answer:
Given: heat energy (Q)=5040 J, mass = 60 g =0.06 kg, Rise in temperature Δt=10K
Specific heat capacity of oil = Heat energy(Q)/Mass (m) x Rise in temperature Δt
=5040J/(0.06kg×40K)
2100Jkg
−1
K
−1
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