Physics, asked by sarahsam, 3 months ago

The temperature of 840g of vegetable oil is raised by adding 110 kJ of heat. The initial
temperature of the oil is 18C and its specific heat capacity is 2,220 J kg-1 K-1.

Calculate the final temperature of the water. SHOW FULL WORKING

Answers

Answered by muskanjangde861
0

Answer:

Given: heat energy (Q)=5040 J, mass = 60 g =0.06 kg, Rise in temperature Δt=10K

Specific heat capacity of oil = Heat energy(Q)/Mass (m) x Rise in temperature Δt

=5040J/(0.06kg×40K)

2100Jkg

−1

K

−1

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