Question

The time interval between two consecutive
minima iftwo tuning forks of frequencies 100
Hz and 110 Hz are vibrated together to produce
beats is
1) 0.1 s 2)1s 3) 0.05 s 4)0.2 s​

Answer 1

Answer:

0.1s

Step-by-step explanation:

110-100=10= frequency

Therefore time=1/10=0.1s