Question

the two bodies have their masses M1 /M2 = 3 and their kinetic energy is given by K.E1/K.E2 1/ 3 the ratio of their velocities is

Answer 1

m1/m2=3
k1/k2=1/3 =(1/2)m1v1²/(1/2)m2v2²=1/3
= m1/v1²/m2v2²=1/3
But,(m1/m2=3)
=3(v1/v2)²=1/3
=(v1/v2)²=1/9
=v1/v2=(1/9)½=1/3

Answer 2

1:3 is the ratio of their velocities.

Explanation:

As we know,

$\frac{m_{1}}{3} = m_{2}$

3$E_{1} = E_{2}$

$E_{1} = 0.5m_{1} v1^{2}$

$E_{2} = 3E_{1} = 0.5m_{2} v2_{2} = 0.5(m_{1}/3) V2_{2}$

9$E_{1} = 0.5m_{1} v2_{2}$

$v1_{2}/v2_{2} = 1/9$

$\frac{v_{1} }{v_{2} } = \frac{1}{3}$

Learn more: Ratio of the velocities

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