Question

The value of 102^1/2 according to binomial theorem is

Answer 1

Given:

$\bold{102^\frac{1}{2}}$

To find:

value by binomial theorem= ?

Solution:

Formula:

$(x+y)^{n}=\sum _{k=0}^{n}{n \choose k}x^{n-k}y^{k}=\sum _{k=0}^{n}{n \choose k}x^{k}y^{n-k}$

Solve:

$102^\frac{1}{2} = (100+2)^\frac{1}{2}$

To put the value = $(100+2)^\frac{1}{2}$ in the above formula we get the value that is: 10.09

OR

To check the value we simply calculate the square root of $\sqrt{102}$  that is equal to 10.09

The final answer is: 10.09.

Answer 2

Answer:

10.1

Step-by-step explanation:

I'm doing it by binomial approximation,

(102)^1/2 = (100+2)^1/2

taking 10 as common,

10(1+2/100)^1/2

10 (1+ 1/2 * 2/100)

10(1+0.01)

=10.1

hope this helps :-)