the value of sin@-cos@=0,then the value of (sin^4@+cos^4@) is plzz give me accurate and helpful sollution and let every one understands by seeing
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Answered by
2
GIVEN -
sin@ - cos@=0
sin @ = cos @
sin@ / cos@ = 1
tan@ = 1
@ = tan inverse 1
@ = π/4
--------
sin^4 π/4+cos^4 π/4
(1/√2)⁴ + (1/√2)⁴
1/4 + 1/4
= 1/2
sin@ - cos@=0
sin @ = cos @
sin@ / cos@ = 1
tan@ = 1
@ = tan inverse 1
@ = π/4
--------
sin^4 π/4+cos^4 π/4
(1/√2)⁴ + (1/√2)⁴
1/4 + 1/4
= 1/2
Answered by
7
Bring it in the form of tan@ ,then find the value of @.
So,
sin@ - cos@ = 0
sin@ / cos@ = 1
We know sin@/ cos@ = tan@
So tan@ = 1
@ = tan^-1
@ = 45°
Now just put the values.
sin^4@ + cos^4@
sin^4 45° + cos^4 45°
1/√2^4 + 1/√2^4
1/4 + 1/4 = 2/4 = 1/2
Hope This Helps You!
So,
sin@ - cos@ = 0
sin@ / cos@ = 1
We know sin@/ cos@ = tan@
So tan@ = 1
@ = tan^-1
@ = 45°
Now just put the values.
sin^4@ + cos^4@
sin^4 45° + cos^4 45°
1/√2^4 + 1/√2^4
1/4 + 1/4 = 2/4 = 1/2
Hope This Helps You!
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