The volume of water that must be added to a mix of 250 ml of 0.6 m hcl and 750 ml of 0.2m hcl to obtain 0.25 m solution of hcl is
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Answer:
1.2l
Explanation:
Quantity of the solution = 250 and 750 ml (Given)
Hcl = 0.6m and 0.2m (Given)
Number of moles of 0.6M HCl = 0.15
Number of moles of 0.2M HCl = 0.15
Let V be the volume of the specified 0.25M solution.
Thus,
No of moles present = 0.15+0.15 = 0.3
Therefore -
= 0.3 × 1000/v(ml) = 0.25 M
= 1.2
Thus to obtain the hcl solution 1.2l of solution is required.
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