Question

The weight of substance deposited is 1.34
g,calculate current in amperes when the
process of electrolysis is carried for 10
minutes. Given ECE=0.001118​

Answer 1

Explanation:

The mass of the substance deposited when one Faraday of charge is passed through its solution is equal to gram equivalent weight. For example, when one Faraday of charge is passed through AgNO

3

solution, 108 g of silver is deposited at the cathode.

Note:

One Faraday of charge corresponds to one mole of electrons.

Answer 2

The current produced when the process of electrolysis is carried out for 10 minutes is 2A.

Given:

The weight of the substance deposited is 1.34g, the process of electrolysis is carried out for 10 minutes, and ECE=0.001118.

To Find:

The current.

Solution:

To find the current in amperes when the

process of electrolysis is carried for 10

minutes.

Current can be calculated by using the faradays law of electricity because as per the law weight deposited on the electrode depends on the amount of current flowing.

So,

$w = zIt$

According to the question:

Weight deposit = 1.34 g

Time (t) = 10 minutes = 10 × 60 = 600 sec.

(1 minute = 60 seconds.)

I =?

Now,

Putting values in the above formula we get,

$1.34 = 0.001118 \times I \times 600$

$I = \frac{1.34}{0.001118 \times 600} = 2A$

Henceforth, the current produced when the process of electrolysis is carried out for 10 minutes is 2A.

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