There are 576 boys and 448 girls in a school that have to be divided into equal section of either boys or girls alone. Find the total number of section thus formed?
Answers
Answered by
21
576 = 2*2*2*2*2*2*3*3;
448 = 2*2*2*2*2*2*7;
HCF = 2*2*2*2*2*2 = 64;
Hence, number of classes required;
(576/64)+(448/64)
= 9+7 = 16.
Short-Cut:
The numbers (3*3) and 7 are not a part of HCF. And sum of multiplication of these number is the required answer.
448 = 2*2*2*2*2*2*7;
HCF = 2*2*2*2*2*2 = 64;
Hence, number of classes required;
(576/64)+(448/64)
= 9+7 = 16.
Short-Cut:
The numbers (3*3) and 7 are not a part of HCF. And sum of multiplication of these number is the required answer.
Answered by
6
Answer:
The total numbers of sections thus formed are 16.
Step-by-step explanation:
Given:
Number of boys in school = 576
Number of girls in school = 448
Height Common Factor ( HCF ) of both number gives the number of students in a section then we divide each number with HCF to get number of sections.
Prime factorization,
576 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3
448 = 2 × 2 × 2 × 2 × 2 × 2 × 7
HCF of 576 & 448 = 2 × 2 × 2 × 2 × 2 × 2 = 64
Number of sections of Boys = 576/64 = 9
Number of sections of girls 448/64 = 7
Number of sections = 9 + 7 = 16
Therefore, The total numbers of sections thus formed are 16.
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