Question

There are two types of ore. First ore contains 68% iron , second ore contains 63% iron. Find the amount of each that will contain 65% of iron in 100 ton of ore????? Plz answer with appropriate steps.

Answer 1

From the inquiry, 100kg of a metal contains 15kg of iron. Let mass required to acquire 18kg of iron be 'x'.  

At that point, 15/100 * x = 18kg ⇒ x = 1800kg/15 = 120kg.

In this way, mass required to acquire 18kg of iron is '120kg'. It needs 120 kg of metal to get 18 kg of iron.

Answer 2

Answer:

$\bold\red{ 120\: is \:the \: correct \: answer}$

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