Question

SecAcotB-secA-2cotB+2=0 find acute angle Aand B satisfying

Answer 1

A and B should be in acute angles and it is trying to most possible numbers and it should finds between 30 and 45 to satisfy the number. sin20c + sin2(π/6)c + sin2(π/3)c + sin2(π/2)c = (0)2 + (1/2)2 + (√3/2)2 + (1)2. = 0 + 1/4 + ¾. So, the A and B value is SecA and CotB-secA-2cotB+2=0.

Answer 2

Answer:

$\bold\red{ 0 \: is \:the \: correct \: answer}$

#answerwithquality #bal

$\rule{300}{2}$