Math, asked by indrajadhavrao518, 1 year ago

There was 120 litres of pure milk in a vessel. some quantity of milk was taken out and replaced with 23 litres of water in such a way that the resultant ratio between the quantities of milk and water in the mixture was 4 : 1 respectively. again 23 litres of the mixture was taken out and replaced with 27 litres of water. what is the respective ratio of milk and water in the resultant mixture

Answers

Answered by selectivelyavailable
5

Answer:

answer is................

368 : 227

Attachments:
Answered by RvChaudharY50
0

Solution ;-

Let us assume that, x quantity of milk was taken out and replaced with 23 litre of water.

so, given that,

→ Milk : water = 4 : 1

→ (120 - x) : 23 = 4 : 1

→ (120 - x) / 23 = 4/1

→ 120 - x = 23 * 4

→ 120 - x = 92

→ x = 120 - 92

→ x = 28 litre.

Now, in the Mixture we have :-

Milk = 120 - 28 = 92 litre .

water = 23 litre .

given that, again 23 litre of mixture was taken out and replaced with 28 litre of water .

then,

→ Quantity of milk was taken out in 23 litre of mixture = (4/5) * 23 = 18.4 litre .

and,

→ Quantity of water was taken out in 23 litre of mixture = (1/5) * 23 = 4.6 litre .

therefore,

→ Milk left in mixture now = 92 - 18.4 = 73.6 litre .

and,

→ Water left in mixture now = 23 - 4.6 = 18.4 litre .

now, we have given that, 28 litres of was added.

hence,

→ Milk = 73.6 litre .

→ water = 18.4 + 28 = 46.4 litre .

→ Required ratio = M : W = 73.6 : 46.4 = 184 : 116 = 46 : 29 (Ans.)

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