Physics, asked by ZiaAzhar89, 11 months ago

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Answered by anamikapradeep7
3

hey mate...

here is your answer...

the position of the particle at a time t is given as :

x(t) = v0/a(1-e-at)

as x denotes position, (x) = m, i.e distance in meter.

here the exponential, e^at must be dimesionless.

hence (a) = s^-1 or inverse time.

or a = (M0 L0 T^-1)

--> (V0) / (a) = (V0) s = m

hence V0 has dimensions of velocity, i.e (V0) = ms ^ -1.

or V0 = (M0 LO T^-1)

hope it helps...

Answered by sagarnirapure914
20

Answer:

Hey Sis..........

Option (C) M^0 L^1 T^^-1 & T^-1

respectively..... is correct ✔️✔️✔️

Refer to the attachment for required explanation ✔️✔️✔️

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