three bells tall at intervals of 12 minutes,15 minutes and 18 min respectively . if they start together after . what time they next tall together
Answers
Answered by
4
There are given three bells
The first bell talls at every 12 minutes
The second bell talls at every 15 minutes
The third bell talls at every 18 minutes.
Now,
If all these start when will they tall together
See,
The first bell will ring in the multiples of 12. Like 12,24,36,48,60 and so on.
The second one will tall at multiples of 15
And, third one will tall at mutiples of 18.
We have to find a common number from the multiples of all three and the number should be the smallest common number.
So,
It means we have to find the Least Common Multiple or the LCM
So,
Lcm of 12,15 and 18
12 = 2*2*3
15= 3*5
18 = 2*3*3
Now,
Common numbers from :-
All rows = 3
First two = none (as 3 is already taken)
Last two=none
First and last = 2
So,
Lcm = 3*2*2*3*5 = 180
So,
All three bells will tall togetger after 180 minutes or 3 hours.
The first bell talls at every 12 minutes
The second bell talls at every 15 minutes
The third bell talls at every 18 minutes.
Now,
If all these start when will they tall together
See,
The first bell will ring in the multiples of 12. Like 12,24,36,48,60 and so on.
The second one will tall at multiples of 15
And, third one will tall at mutiples of 18.
We have to find a common number from the multiples of all three and the number should be the smallest common number.
So,
It means we have to find the Least Common Multiple or the LCM
So,
Lcm of 12,15 and 18
12 = 2*2*3
15= 3*5
18 = 2*3*3
Now,
Common numbers from :-
All rows = 3
First two = none (as 3 is already taken)
Last two=none
First and last = 2
So,
Lcm = 3*2*2*3*5 = 180
So,
All three bells will tall togetger after 180 minutes or 3 hours.
Answered by
2
the lcm of 12,15,18 min is 180 so they. next tall together in 3 hours
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