Question

three times the smallest of three consecutive odd number decreased by 7 equal twice the largest one . find the numbers.

Answer 1

Numbers are n,
n+2 and n+4
3n-7 = 2(n+4)
3n-7 = 2n+8
3n-2n = 8+7
n = 15
Ans : 15, 17 and 19

Answer 2

If the first required odd number is taken as x then the three odd numbers will be x, x+2 and x+5.
Now according to question
3(x)-7 = 2(x+4)
3x-7 = 2x+ 8
x=15
ie the numbers are 15, 17 and 19.

hope this helps. :))