Question

to log of X + 1 equal to log 2 + log x find X value

Answer 1

$log (x + 1) = log(2) \: + \: log(x) \\ log(x + 1 ) - log(x) = \: log(2) \\ log( \frac{x + 1}{x} ) = log(2) \\ \frac{x + 1}{x} = 2 \\ x + 1 = 2x \\ 2x - x = 1 \\ x = 1$
hope it will help you...