Question

to push open a door a person apply of a force of 75 Newton acts on the handle of the door at a and 600 from normal to its plane if the hand locates at a distance 80 cm from its hings the torqe applied by him​

Answer 1

Answer:

Torque=60 Nm.

Explanation:​

Since torque is the moment required to rotate the body with a given force and position vector.

Important point:The applied force is always perpendicular to the position vector r.

We know the formula for torque

So,torque=force x perpendicular distance.......................(1)

Here in the given question Force=75 Newtons

And Perpendicular distance=80 cm.

1 metre=100 centimetre

After applying the formula we get,

So, $torque=75\times0.8$

So,torque=60 Nm.

Answer 2

Answer:30

Explanation:F=75,teta =30(because angle is from normal. We should calculate it from horizontal, therefore 30 degrees), r=80cm=0.8m

Torque =r×fsin teta therefore substituting we get, 75×0.8×sin30. 75×0.8×0.5=30