Question

toral no of electrons present in 48g mg2+ are​

Answer 1

Answer:

=1.2044 x 10^25 electrons

Explanation:

Quora. 24 gm of Magnesium contains=N atoms. ... 023 x 10^24 48 gm of Magnesium 48 gm of Mg contains=2 N atoms.

Answer 2

Answer:

120.46*10^23 electrons

Explanation:

to calculate the moles, we use the equation:

number of moles = given mass/mass

for Mg^2+

Mass given = 48g

molar mass of Mg^2+ = 24g/mol

putting values in above equation, we get

Moles of Mg^2+ = 48g/24g/mol = 2mol

Mg : 12 : 1s^2 2s^2 2p^6 3s^2

Mg^2+ : 10 : 1s^2 2s^2 2p^6

according to Avogadro's law, 1 mole of every substance contains Avogadro's number (6.023*10^23) of particles.

1 mole of Mg^2+ will contain:

10*6.023*10^23 = 6.023*10^23 electrons

2 moles of Mg^2+ will contain:

6.023*10^23/1 *2 = 120.46*10^23 electrons.......

hope it helps u.......