Math, asked by shreyamore13, 10 months ago

total amount of Rs 40,000 is invested. a part of it is invested at 4% and rest at 6% p.a. interest of all is Rs 2,130. How much is each investment ?​

Answers

Answered by ganesh6450
0

Answer:

135500

Step-by-step explanation:

  • 40000*100/4*1.
  • now you are going to get answer that is 100000.
  • now same way 2130 *hundred by 6 *1.
  • now we are going to get answer is 35500.
  • if you add both you are going to get answer

nileshbhusare: are u from ckt school?
Answered by sonuvuce
0

Amount invested at 4% per annum = 13500 Rs.

Amount invested at 6% per annum = 26500 Rs.

Step-by-step explanation:

Let P amount is invested at 4% per annum and rest at 6% per annum

Interest in a year = 2130

Here the period must be 1 year as the interest is far less compared to the amount and also the rate given is per annum

Thus,

Using the simple interest formula

I=\frac{nPr}{100}

2130=\frac{1\times P\times 4}{100}+\frac{1\times (40000-P)\times 6}{100}

\implies 213000=4P+40000\times 6-6P

\implies 2P=240000-213000

\implies 2P=27000

\implies P=13500 Rs.

Therefore, amount invested at 4% per annum = 13500 Rs.

Amount invested at 6% per annum = 40000 - 13500 = 26500 Rs.

Hope this answer is helpful.

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