Question

transform the equation x+y+1=0 into normal form

Answer 1

Answer:

The required normal form is $x.cos(\frac{5\pi}{4})+y.sin(\frac{5\pi}{4})=\frac{1}{\sqrt{2}}$

Step-by-step explanation:

Formula used:

Normal form of straight line is

$x\:cos\:\alpha+y\:sin\:\alpha=p$

Given line is x+y+1=0

It can be written as

- x - y =1

divide both sides by $\sqrt{(-1)^2+(-1)^2}=\sqrt{2}$, we get

$x(\frac{-1}{\sqrt{2}})+y(\frac{-1}{\sqrt{2}})=\frac{1}{\sqrt{2}}\\\\x.cos(\frac{5\pi}{4})+y.sin(\frac{5\pi}{4})=\frac{1}{\sqrt{2}}$