Question

Triangle ABC is an isosceles triangle right angled at C. Prove that AB²=2AC²

Answer 1

Considering the triangle given, AC=CB

Using Pythagoras theorem

hypotenuse^2=(one side of triangle^2)+(other side of triangle^2)

AB^2=AC^2+BC^2
AB^2=2AC^2{given AC=BC}

HENCE PROVED

Answer 2

here is your ans,...........