Question

Triangle ABC is isosceles in which AB =AC. segBD & seg CE are medians.show that BD=CE.​

Answer 1

Answer:

in ΔABD AND ΔACE

∠A=∠A (COMMON)

AB=AC (GIVEN)

AD=AE( AB=AC ⇒1/2AB=1/2AC ⇒AD=AE)

ΔABD≅ΔACE (SAS)

BD=CE (CPCT)

Step-by-step explanation:

Answer 2

In triangle AEC AND ADB,

AB=AC(GIVEN)

<AEC =<ADB=90°(GIVEN)

<A=<A(COMMON)

THUS,TRIANGLE AEC CONGRUENT TO ADB BY AAS RULE.

BD = CE BY CPCT.