Math, asked by maddy94, 1 year ago

trigonometry question

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Answered by khushisingh9026

1+sinA/cosA = cosA/1-sinA

L.H.S

=1+sinA/cosA

=cosA(secA+tanA)/{(1-sinA)[(cosA(1+sinA)/(1-sinA)(1+sinA)]}

=cosA(secA+tanA)/(1-sinA)(secA+tanA)

=cosA/1-sinA

=R.H.S

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