trigonometry question
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1+sinA/cosA = cosA/1-sinA
L.H.S
=1+sinA/cosA
=cosA(secA+tanA)/{(1-sinA)[(cosA(1+sinA)/(1-sinA)(1+sinA)]}
=cosA(secA+tanA)/(1-sinA)(secA+tanA)
=cosA/1-sinA
=R.H.S
L.H.S
=1+sinA/cosA
=cosA(secA+tanA)/{(1-sinA)[(cosA(1+sinA)/(1-sinA)(1+sinA)]}
=cosA(secA+tanA)/(1-sinA)(secA+tanA)
=cosA/1-sinA
=R.H.S
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