Two balls are dropped from heights h and 2h respectively. What would be the ratio of times
taken by the balls to reach the earth ?
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for first ball,
distance =h,u=0,t=?
s=ut+1/2gt^2
h=1/2gt^2
2h/g=t^2----(1)
for second ball,
u=0,distance=2h,
s=ut+1/2gT^2
2h=1/2gT^2
4h/g=T^2-----(2)
By (1)/(2)
t/T=1:2
distance =h,u=0,t=?
s=ut+1/2gt^2
h=1/2gt^2
2h/g=t^2----(1)
for second ball,
u=0,distance=2h,
s=ut+1/2gT^2
2h=1/2gT^2
4h/g=T^2-----(2)
By (1)/(2)
t/T=1:2
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