two dies are thrown simultaneously find the probability of getting.a) double of a even numbers.
Answers
Answered by
0
total outcomes=36
double of even numbers=3 (2,2;4,4;6,6)
p (E)=3/36
=1/12
double of even numbers=3 (2,2;4,4;6,6)
p (E)=3/36
=1/12
Answered by
0
n(S) = 36
event A = double of even numbers
therefore, A = 2{ (2,2) , (4,4) ,(6,6) }
n(A) = 3/36
therefore n(A) = 1/12.
event A = double of even numbers
therefore, A = 2{ (2,2) , (4,4) ,(6,6) }
n(A) = 3/36
therefore n(A) = 1/12.
Similar questions
Math,
7 months ago
Environmental Sciences,
7 months ago
English,
1 year ago
English,
1 year ago
India Languages,
1 year ago
India Languages,
1 year ago