Question

Two numbers are 30 and 37 per cent less than a third
number. How much per cent is the second number less than
the first?
37​

Answer 1

Answer:

Let the third number be 100

The first number is 70 and second number is 63.

% the second number is less than the first

=

70

(70−63)

×=

70

7

×100 = 10%

Answer 2

Given:-

• Two numbers are 30 and 37 per cent less than a third number.

To find:-

• percent is the second number less than the first.

Solution:-

Let,

• the third number be x.

Then the first number:-

→ (100 - 30)℅ of x

→ 70℅ of x

→ 7x/10

Difference:-

→ 7x/10 - 63x/100

→ 7x/10

So,

• required percentage is, difference is what percent of first number

→ (7x/100 × 10/7x × 100)℅

→ 10℅

Hence,

• Percent is the second number less than the first is 10℅.