two numbers are in the ratio 3 is to 5 if 9 is subtracted from each the new number are in the ratio 12 is to 23 find the number
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let the number be x
ratio is 3:5
(3x-9)/5x-9=12x/23x
69x^2-207x=60x^2-108x
9x^2=99x
x=11
the numbers are 33 and 55
ratio is 3:5
(3x-9)/5x-9=12x/23x
69x^2-207x=60x^2-108x
9x^2=99x
x=11
the numbers are 33 and 55
AFFAN16:
don't understand
Answered by
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A/q
x/y=3/5
∴y=5x/3----------(1)
and
(x-9)÷(y-9) = 12÷23
∴23x-207=12y-108
23x=12y+99
23x=12×5x÷3 +99
∴x=33
putting the value of x=33 in (1) we get y=55
∴The reqd. nos are 33 and 55
x/y=3/5
∴y=5x/3----------(1)
and
(x-9)÷(y-9) = 12÷23
∴23x-207=12y-108
23x=12y+99
23x=12×5x÷3 +99
∴x=33
putting the value of x=33 in (1) we get y=55
∴The reqd. nos are 33 and 55
don't understand
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