Question

Two poles of heights 6m and' 11m stand
on å plane ground if . the distance between
their feet is 12m find the distance between
their tops​

Answer 1

Answer:

13m

Step-by-step explanation:

Length of poles are 6m and 11m.

Distance between their feet = 12m

Lets join the top of the poles with line

Now, we can form a triangle at the top considering the base length (distance between feet) which will remain same till top Hence, base of triangle, B = 12

Now we have to find out the height of the triangle, which can be find out by subtracting the lengths of the pole so,

Height, H = 11-6=5

Now, the triangle formed is right angled triangle as the poles are parallel to base, hence they form the right angle.

Now, by Pythagoras theorem

${hypotenuse}^{2} = {base}^{2} + {height}^{2} \\ {hypotenuse}^{2} = {12}^{2} + {5}^{2} \\ {hypotenuse}^{2} = 144 + 25 \\ {hypotenuse}^{2} = 169 \\ {hypotenuse} = \sqrt{169} = 13$

Hence, the distance between top of poles is 13m