Question

two resistors of 6 ohms and 3 to be connected to a battery of 9 volt so as to obtain minimum current and Maximum current in the circuit how will you connect the resistors to the battery in each case calculate the total current flowing in the circuit in both the cases

Answer 1

Maximum current:-

To obtain minimum current the resistors are to be connected in series.

R = r1 + r2

  = 6 + 3 ohms

  = 9 ohms

V = IR

I = V/R

 = 9/9

 = 1 ampere

For minimum current

To obtain maximum current the resistors are to be connected in parallel.

1/R = 1/r1 + 1/r2

     = 1/6 + 1/3

      = 1 + 2 /6

      = 3/6

      = 1/2

R = 2

V = I R

I = V/R

 = 9/2

 = 4.5 amperes

Hope this helped!

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Answer 2

4.5 amperes

hope hepld