Question

Two squares and an equilateral triangle,find the angle​

Answer 1

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Answer 2

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HERE IS UR ANSWER

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c=a+b

we know AP=PC=c/2

by pythagoras property

${bc}^{2} = {bp}^{2} + {pc}^{2}$

${c}^{2} = {bp}^{2} + ( \frac{c}{2}) {}^{2}$

$bp = \frac{ \sqrt{3c} }{4}$

BG=BP-PG

$bg = \frac{ \sqrt{3c} }{4} - b$

$\tan(x) = \frac{ \sqrt{3}c - 4b }{2c}$