Using Euclid's division algorithm, find whether the pair of numbers 847, 2160 are coprimes or not.
Answers
Answered by
13
hello friend,
2160 = 2 * 847 + 466
847 = 1 * 466 + 381
466 = 4 * 85 + 41
85 = 2 * 41 + 3
41 = 13 * 3 + 2
3 = 1 * 2 + 1
2 = 1 * 1
thus the hcf of 847 and 2160 is 1.
and the given numbers are coprimes
hope it hepls u
2160 = 2 * 847 + 466
847 = 1 * 466 + 381
466 = 4 * 85 + 41
85 = 2 * 41 + 3
41 = 13 * 3 + 2
3 = 1 * 2 + 1
2 = 1 * 1
thus the hcf of 847 and 2160 is 1.
and the given numbers are coprimes
hope it hepls u
invincible007:
your last step is wrong
Answered by
11
Hi Friend,
10 , 7 , 4 , ...... , ( -62 ) are in A.P
a(FIRST TERM) = 10
d(COMMON DIFFERENCE) = a3 - a2 = 4 - 7 = -3
last term = n th term = an = l = - 62
THEREFORE, WE WILL APPLY THE NTH TERM FORMULA
a + ( n - 1 ) d = l
10 + ( n - 1 ) ( - 3 ) = -62
( n- 1 ) ( -3 ) = -62 - 10
( n - 1 ) ( - 3 ) = - 72
( n - 1) = ( - 72 ) / ( - 3 )
n - 1 = 24
n= 24 +1
n = 25
Number of terms in given A. P = n= 25
middle term = ( n+ 1 ) /2 th term
= (25 +1) / 2 th term
= 26 /2 th term
= 13 th term
iii) a = 10 , d= -3 , n= 13
a13 = ?
a13 = a + 12d
= 10 + 12 × ( -3 )
= 10 - 36
= -26
Middle term in given in A. P = a 13 = -26
10 , 7 , 4 , ...... , ( -62 ) are in A.P
a(FIRST TERM) = 10
d(COMMON DIFFERENCE) = a3 - a2 = 4 - 7 = -3
last term = n th term = an = l = - 62
THEREFORE, WE WILL APPLY THE NTH TERM FORMULA
a + ( n - 1 ) d = l
10 + ( n - 1 ) ( - 3 ) = -62
( n- 1 ) ( -3 ) = -62 - 10
( n - 1 ) ( - 3 ) = - 72
( n - 1) = ( - 72 ) / ( - 3 )
n - 1 = 24
n= 24 +1
n = 25
Number of terms in given A. P = n= 25
middle term = ( n+ 1 ) /2 th term
= (25 +1) / 2 th term
= 26 /2 th term
= 13 th term
iii) a = 10 , d= -3 , n= 13
a13 = ?
a13 = a + 12d
= 10 + 12 × ( -3 )
= 10 - 36
= -26
Middle term in given in A. P = a 13 = -26
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