Question

using newton's law, show that the value of 'g' decreases as one goes above the earth's surface

Answer 1

$force = m1 \times m2 \div {d}^{2} \\ force = mass \times acceleration \\ mass \times acceleration = m1 \times m2 \div {d}^{2} \ \\ (here \: mass \: divides \: m1) \\ so \: \: accn = m2 \div {d}^{2} \\ (and \: because \: accn \: is \: inversily \: proportion \: to {d}^{2} \: so \: accn \: must \: distrbed \: due \: to \: increasment \: and \: decreasment \: in \: distance$