Math, asked by Tomboyish44, 1 year ago

Using suitable identity evaluate, (-32)^3 + (18)^3 + (14)^3

Answers

Answered by sparkMark
14
a=-32
b=18
c=14

-32+18+14=0
= 3abc
3(-32)(18)(14)
-24192
Answered by Anonymous
9

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Using suitable identity evaluate, (-32)^3 + (18)^3 + (14)^3?

Step-by-step explanation:

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Let a=−32,b=18,c=14

a+b+c=−32+18+14=0

As we know that

If a+b+c=0 then a3+b3+c3=3abc

So (−32)3+(18)3+(14)3=3(−32)(18)(14)=−24192

THEREFORE THE ANSWER IS \huge\red{-24192}{\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {blue} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@MAYU----}}}}}}}}}}}}}}}

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