Question

विस्तार करा: $\bigg \lgroup y - \frac{3}{y}\bigg \rgroup ^{2}$

Answer 1

प्रश्नः

विस्तार करा: ${(y - \frac{3}{y} )}^{2}$

उत्तरः

सुत्र: (a - b)² = a² + b² - 2ab

$= > {(y - \frac{3}{y} )}^{2} \\ \\ = > {(y)}^{2} + {( \frac{3}{y}) }^{2} - 2(y)( \frac{3}{y} ) \\ \\ = > {y}^{2} + \frac{9}{ {y}^{2} } - 6$

Answer 2

╔═❤️══════════════╗

...HERE GØΣS UR ANS...

╚══════════════❤️═╝

$\huge{\boxed{\bold{\mathfrac{\red{Solution}}}}}$

$\boxed{\red{ {(a - b)}^2 = a^2 + b^2 - 2ab}}$

$\bigg \lgroup y - \frac{3}{y}\bigg \rgroup ^{2}$

$\ ={(y)}^2 + {( \frac{3}{y}) }^2 - 2(y)( \frac{3}{y} )$

$\ =y^2 + \frac{9}{ y^2 } - 6$

╔═❤️══════════════╗

   ⓉⒽⒶⓃⓀⓈ

╚══════════════❤️═╝