Question

Volume occupied by 2.2g CO2 at STP is

Answer 1

Answer: 1.12L

Explanation:

1 mole of CO2 = 22.4 L

44g of CO2 = 22.4L

1g of CO2 = 22.4/44 L

2.2g of CO2 = 22.4/44 * 2.2

= 1.12L

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