what is formula for tan inverse x minus tan inverse y = ? , if xy = 1
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he answer is............
tan^-1 (x) + tan^-1 (y) = tan^-1 [(x+y) / (1-x*y)]
and ,.
x y = 1
tan^-1 (1/y) + tan^-1 (1/x)
= tan^-1 [(1/y+1/x)/(1-1/y*1/x)]
= tan^-1{[(x+y/(xy)/(1-1/(xy)}
put xy= 1
= tan^-1 {[(x+y/(1))/(1-1/(1)]}
= Tan^-1{[(x+y)/(1-1)]}
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