Question

What is ratio of moment of inertia of two ring of radius r and nr about an Axis perpendicular to their plane and passing through their centre?​

Answer 1

Answer:

Explanation:

Two rings of radius R and nR made of same material have the ratio of moment of inertia about an axis passing through center is 1:8.

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Answer 2

Given: Two rings of radius r and nr

To find: Ratio of their Moment of Inertia

Solution:

The moment of inertia of a ring about an axis perpendicular to the plane and passing through the center is given by: MR².

Here,

M=Mass

R=Radius

Moment of Inertia (MI) of a ring of r radius = Mr²  --------(i)

Moment of Inertia (MI) of a ring of r radius= M(nr)² = Mn²r² -------(ii)

On dividing (i) by (ii)

The ratio comes out to be:

Mr²/ Mn²r² = 1/n²