Question

What is the 1025h term of the sequence 1, 2, 2, 4,4,4,4,8, 8, 8, 8, 8, 8, 8, 8......2​

Answer 1

Answer:

$1 + 2 + 4 + 8 + ....n \: terms = 1025$

G.P sum formula,

$1( {2}^{n} - 1) = 1025$

${2}^{n} = 1024 = {2}^{10}$

$n = 10$

so 10th term of GP is,

$a_{10} = a \times {r}^{n - 1} = 1 \times {2}^{10 - 1} = {2}^{9}$

$1025th \: term = {2}^{9} = 512$

Mark BRAINLIEST if this is helpful. thanks