Math, asked by isro48, 1 year ago

what is the answer of this question...???

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Answers

Answered by Anonymous

Answer:

OPTION C

Step-by-step explanation:

$\mathsf{^{10}C_{0}^{20}C_{10}-^{10}C_1^{18}C_{10}+.............}\\\\\bf{By\:Binomial\:theorem\::}\\\\\mathsf{Coefficient\:of\:x^{10}\:in\:^{10}C_0 (1 + x)^{20}-^{10}C_1(1 + x)^{18} +......}\\\\\implies \mathsf{ Coefficient\:of\: x^{10}\:in\: (^{10}C_0 ((1 + x)^2)^{10}-^{10}C_1((1 + x)^2)^9...........)}\\\\\implies\mathsf{Coefficient\:of\:x^{10}\:in\:((1+x^2)-1)^{10}}\\\\\implies \mathsf{Coefficient\:of\:x^{10}\:in\:(1+x^2+2x-1)^{10}}\\\\\mathsf{Coefficient\:of\:x^{10}\:in\:(2x+x^2)^{10}}\\\\$

$\implies\mathsf{2^{10}}$

Answered by generalRd

Hi

Here is your answer

Hope it helps and mark me brainliest

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