What is the formula of HCF and LCM or relation between them ???
**class 10** ( chapter 1 :Real Numbers)
AND is this division in the above attachment is right?? If not where is the mistake?
If yes I want an explanation of second step!!!
plz i want an valid answer for my question, no spam plz
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Answered by
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The relation between HCF and LCM is
HCF (a,b) × LCM (a,b) = a×b
Yes, the division in the above attachment is right.
HCF (a,b) × LCM (a,b) = a×b
Yes, the division in the above attachment is right.
prolita30ovuwfv:
if u like it, mark it as brainliest.
what is (a, b) here?
numbers?
yes, numbers
and plz say the second step I can't understand
in second step, we multiplied -1 so, x becomes -x and +2 becomes -2. Now, we have to change the signs. -x will be + x and -2 will be +2 . and so, the remainder is 1+2=3
Answered by
0
hcf(a, b) times lcm(a, b) = ab
and division is correct
Step-by-step explanation:
in step 2, we subtract the polynomial we get by -1 as we have to subtract. that is why we choose a number such when multiplied, it gives the same number as what we are dividing
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