Question

what is the probability that an ordinary year has 53 sundays? ​

Answer 1

Answers

SOLUTION :

Given : An ordinary year.

Total number of days in ordinary year = 365 days .It contain 52 weeks and 1 day

This one day can be any day of the week :

Sunday, Monday, Tuesday, Wednesday, Thursday, Friday and Saturday.

Here, we have to make 53 Sundays so one additional day should be Sunday.

Total number of days = 7

Total number of outcomes = 7

Let E = Event of getting an ordinary year which has 53 Sundays

Number of favourable outcomes : 1 (Sunday)

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E) = 1/7

Hence, Probability of getting an ordinary year which has 53 Sundays, P(E) = 1/7 .

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Answer 2

Answer:

1/7

Step-by-step explanation:

Total number of days in ordinary year = 365 days . It contains 52 weeks and 1 day

This one day can be any day of the week :  Sunday, Monday, Tuesday, Wednesday, Thursday, Friday and Saturday.

Here, we have to make 53 Sundays so one additional day should be Sunday.

Total number of days = 7

Total number of outcomes = 7

Let E = Event of getting an ordinary year which has 53 Sundays

Number of favourable outcomes = 1 (Sunday)

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E) = 1/7  Hence, Probability of getting an ordinary year which has 53 Sundays, P(E) = 1/7 .