Physics, asked by rohithn, 11 months ago

What is the radius of curvature of a convex mirror which forms an image one fourth of the size of an object, when the
object is placed 6 m in front of the mirror

Answers

Answered by azizalasha
11

Answer:

240 cm.

Explanation:

y/x = 1/4 . y = x/4

1/f= 1/x + 1/y  = 1/x + 4/x = 5/x = 5/600 = 1/120

f = 120cm.

R = 2f = 240 cm.

     

Answered by bskeerthi
0

I think,

y/x = 1/4 . y = x/4

1/f= 1/x + 1/y  = 1/x + 4/x = 5/x = 5/600 = 1/120

f = 120cm.

R = 2f = 240 cm.

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