Question

What is the resultant of two vectors 6kgf and 8kgf acting at a point at an angel of 60degree

Answer 1

Answer:

Explanation:

Use the Cosine Rule. Vinod seemed to use it, but it's not clear where the “1/2” in his equation came from.

The cosine rule is given by

a2=b2+c2−2bc

×Cos(A)

Let a=resultant, b=6, c=8 and A=120°

(120° is the supplementary angle of 60°)

a2=62+82−2(6)(8)Cos(120)

a2=148

a≈12.17

To help visualize you can use, what's called, the parallelogram method.

Answer 2

Answer:

Use the Cosine Rule. Vinod seemed to use it, but it's not clear where the “1/2” in his equation came from.

The cosine rule is given by

a2=b2+c2−2bc

×Cos(A)

Let a=resultant, b=6, c=8 and A=120°

(120° is the supplementary angle of 60°)

a2=62+82−2(6)(8)Cos(120)

a2=148

a≈12.17

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